Unit & Currency Converters

Temperature Converter

Convert temperatures between Celsius, Fahrenheit, and Kelvin with absolute-zero validation.

Temperature Converter — Online Calculator

Temperature Converter

Edit any scale to update the other two instantly.

21°C equals 69.8°F and 294.15 K.
Absolute zero
-273.15°C
Water freezes
0°C
Room temperature
21°C
Water boils
100°C
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The Temperature Converter provides precise two-way conversions across all major thermodynamic and empirical temperature scales: Celsius (°C), Fahrenheit (°F), and Kelvin (K). Built on fundamental physical thermodynamic constants, the tool includes strict validation to reject unphysical temperatures below absolute zero (0 K=−273.15 ∘C=−459.67 ∘F0\text{ K} = -273.15\text{ }^\circ\text{C} = -459.67\text{ }^\circ\text{F}).

Core Temperature Conversion Formulas

Unlike length or mass conversions that simply require multiplying by a scaling constant, temperature conversions (except Kelvin to Rankine) involve an affine transformation with both a proportional scale multiplier and a baseline offset shift.

1. Celsius and Fahrenheit Transformations

Fahrenheit to Celsius:∘C=(∘F−32)×59\text{Fahrenheit to Celsius:}\quad ^\circ\text{C} = (^\circ\text{F} - 32) \times \frac{5}{9} Celsius to Fahrenheit:∘F=(∘C×95)+32=(∘C×1.8)+32\text{Celsius to Fahrenheit:}\quad ^\circ\text{F} = \left(^\circ\text{C} \times \frac{9}{5}\right) + 32 = (^\circ\text{C} \times 1.8) + 32

2. Celsius and Kelvin Transformations

Kelvin is the SI base unit of thermodynamic temperature, where each degree interval is identical in magnitude to one Celsius degree (1 K=1 ∘C1\text{ K} = 1\text{ }^\circ\text{C}): Celsius to Kelvin:K=∘C+273.15\text{Celsius to Kelvin:}\quad \text{K} = ^\circ\text{C} + 273.15 Kelvin to Celsius:∘C=K−273.15\text{Kelvin to Celsius:}\quad ^\circ\text{C} = \text{K} - 273.15

3. Direct Fahrenheit and Kelvin Transformations

Fahrenheit to Kelvin:K=(∘F−32)×59+273.15\text{Fahrenheit to Kelvin:}\quad \text{K} = (^\circ\text{F} - 32) \times \frac{5}{9} + 273.15 Kelvin to Fahrenheit:∘F=(K−273.15)×95+32\text{Kelvin to Fahrenheit:}\quad ^\circ\text{F} = (\text{K} - 273.15) \times \frac{9}{5} + 32

Critical Physical Reference Points

| Physical Phenomenon | Celsius (°C) | Fahrenheit (°F) | Kelvin (K) | | :--- | :--- | :--- | :--- | | Absolute Zero (Third Law limit) | −273.15 ∘C-273.15\text{ }^\circ\text{C} | −459.67 ∘F-459.67\text{ }^\circ\text{F} | 0.00 K0.00\text{ K} | | Freezing Point of Water (1 atm) | 0.00 ∘C0.00\text{ }^\circ\text{C} | 32.00 ∘F32.00\text{ }^\circ\text{F} | 273.15 K273.15\text{ K} | | Triple Point of Pure Water | 0.01 ∘C0.01\text{ }^\circ\text{C} | 32.018 ∘F32.018\text{ }^\circ\text{F} | 273.16 K273.16\text{ K} | | Average Human Body Temperature | 37.00 ∘C37.00\text{ }^\circ\text{C} | 98.60 ∘F98.60\text{ }^\circ\text{F} | 310.15 K310.15\text{ K} | | Boiling Point of Water (1 atm) | 100.00 ∘C100.00\text{ }^\circ\text{C} | 212.00 ∘F212.00\text{ }^\circ\text{F} | 373.15 K373.15\text{ K} |

Step-by-Step Worked Conversion Example

Example: Converting Human Fever (102.2 ∘F102.2\text{ }^\circ\text{F}) to Celsius and Kelvin

  1. Subtract the freezing offset: 102.2−32=70.2102.2 - 32 = 70.2
  2. Multiply by the fraction 59\frac{5}{9}: ∘C=70.2×59=3519=39.0 ∘C^\circ\text{C} = 70.2 \times \frac{5}{9} = \frac{351}{9} = \mathbf{39.0\text{ }^\circ\text{C}}
  3. Convert result to thermodynamic Kelvin: K=39.0+273.15=312.15 K\text{K} = 39.0 + 273.15 = \mathbf{312.15\text{ K}}

Frequently Asked Questions

At what temperature are Celsius and Fahrenheit identical?

Celsius and Fahrenheit scales intersect at exactly −40∘-40^\circ (i.e., −40 ∘C=−40 ∘F-40\text{ }^\circ\text{C} = -40\text{ }^\circ\text{F}). Setting C=FC = F in the formula yields: C=1.8C+32  ⟹  −0.8C=32  ⟹  C=−40C = 1.8C + 32 \implies -0.8C = 32 \implies C = -40

Why does the Kelvin scale not use a degree symbol (°)?

Kelvin is an absolute thermodynamic temperature scale rather than an arbitrary empirical interval. Units on an absolute scale are called kelvins (symbol: K\text{K}), not "degrees Kelvin".

Limitations

This tool performs mathematical conversions based on standardized international temperature definitions (ITS-90). Real-world thermodynamic measurements are subject to sensor tolerance, atmospheric pressure variations at altitude, and local humidity.

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